Re: MATRIX ARITHMETIC II (even rows)

Posted by Anonymous on 2007/6/4 18:36:03

Hi Futari & All Viewers interested in this thread.

Tim must be busy, so I thought I do it manually here.

Here are some clues...

There’s no secret to my formula; just some hard thinking that’s all.

Firstly, position the 64 numbers in running sequence as illustrated below.

01 02 03 04 05 06 07 08 = 036
09 10 11 12 13 14 15 16 = 100
17 18 19 20 21 22 23 24 = 164
25 26 27 28 29 30 31 32 = 228
33 34 35 36 37 38 39 40 = 292
41 42 43 44 45 46 47 48 = 356
49 50 51 52 53 54 55 56 = 420
57 58 59 60 61 62 63 64 = 484

232 240 248 256 264 272 280 288 = 2,080÷8
= 260

You will find that all the numbers add up to 2,080. The Magic Constant of 260 is derived by dividing the sum by 8 (Order 8 as it is called).

Secondly, by arranging the numbers in the sequence as shown, each of the sum of the two individual diagonal lines supernaturally add up to the Magic Constant of 260. This means to say that those numbers in the two diagonal lines stay put.

Over to you and all those interested. Shouldn’t be too difficult from here. Just juggle the numbers here and there, and you will have the solution.

Cheers.

geo