Yet unsolved!

Hi Everybody

Here’s another very strong clue …

A B C D E F G H

S 01 02 03 04 05 06 07 08 = 036

T 09 10 11 12 13 14 15 16 = 100

U 17 18 19 20 21 22 23 24 = 164

V 25 26 27 28 29 30 31 32 = 228

W 33 34 35 36 37 38 39 40 = 292

X 41 42 43 44 45 46 47 48 = 356

Y 49 50 51 52 53 54 55 56 = 420

Z 57 58 59 60 61 62 63 64 = 484

232 240 248 256 264 272 280 288 = 2,080

Note the individual total sum of Columns A ~ H. Each number is smaller by 8 as you move on to the next column. A + H = 232 + 288 = 520. Divide this by 2 to arrive at the Constant Magic of 260. The same goes for B + G; C + F and D + E.

Similarly, if you look at the individual sum of Rows S ~ Z, you will notice that each sum is smaller by 64 if you move downwards. S + Z = 36 + 484 = 520. Again, if you divide this by 2, you’ll arrive at the Constant Magic of 260; and so on ...

Remember not to move the numbers that are locked in the 2 diagonal lines.

There aren’t any other clues clearer than this to solve the riddle. Of course, mine is a secret! Ha ha!

Good Luck.

ps: Sorry for the text distortion. If only Tim is free to help.

Voila!

01 02 62 61 60 59 07 08
09 10 54 53 52 51 15 16
48 47 19 20 21 22 42 41
40 39 27 28 29 30 34 33
32 31 35 36 37 38 26 25
24 23 43 44 45 46 18 17
49 50 14 13 12 11 55 56
57 58 06 05 04 03 63 64

Felicitations! C'est vous encore! Tres bien!
(I hope the words are correctly used)

a la votre