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Re: MATRIX ARITHMETIC II (even rows) |
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Guest_
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Hello Alexia
You'll never succeed if you don't even try. Make an attempt. I can provide clues if so required
Posted on: 2007/3/31 15:24
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Re: MATRIX ARITHMETIC II (even rows) |
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Posted on: 2007/4/1 2:14
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Re: MATRIX ARITHMETIC II (even rows) |
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Guest_
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Hello 美人
Okay, okay! I’ll do it again. Hey Viewers. It’s time again for a solution to Matrix Arithmetic II. Construct a 64-square diagram. Fill in the squares with numerals 1 ~ 64 to obtain the same overall total sum on all vertical, horizontal, and the 2 diagonal lines. Each number may be used only once. All 64 numerals must be used. Good luck.
Posted on: 2007/4/1 10:01
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Home away from home
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06 61 04 59 08 63 02 57
60 03 62 05 58 01 64 07 53 14 51 12 55 16 49 10 11 52 13 54 09 50 15 56 46 21 44 19 48 23 42 17 20 43 22 45 18 41 24 47 29 38 27 36 31 40 25 34 35 28 37 30 33 26 39 32 : : : : : : : : : : : ==> http://www.answers.com/magic%20square
Posted on: 2007/6/1 14:13
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Re: MATRIX ARITHMETIC II (even rows) |
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Guest_
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Hi Lady,
Congratulations! It's YOU again. Brilliant. From the link provided, I can see two different solutions to my riddle. I have a third solution that is proprietary to me. Wanna attempt?
Posted on: 2007/6/1 15:19
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Home away from home
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Working on it. Any hints?
Posted on: 2007/6/3 2:58
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Re: MATRIX ARITHMETIC II (even rows) |
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Guest_
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Hi Lady Futari
& all others interested in this riddle Sure! I have sent Tim an email with attachment showing the clues to this riddle. Just a little patience, please. Cheers. geo
Posted on: 2007/6/4 10:31
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Re: MATRIX ARITHMETIC II (even rows) |
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Guest_
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Hi Futari & All Viewers interested in this thread.
Tim must be busy, so I thought I do it manually here. Here are some clues... There’s no secret to my formula; just some hard thinking that’s all. Firstly, position the 64 numbers in running sequence as illustrated below. 01 02 03 04 05 06 07 08 = 036 09 10 11 12 13 14 15 16 = 100 17 18 19 20 21 22 23 24 = 164 25 26 27 28 29 30 31 32 = 228 33 34 35 36 37 38 39 40 = 292 41 42 43 44 45 46 47 48 = 356 49 50 51 52 53 54 55 56 = 420 57 58 59 60 61 62 63 64 = 484 232 240 248 256 264 272 280 288 = 2,080÷8 = 260 You will find that all the numbers add up to 2,080. The Magic Constant of 260 is derived by dividing the sum by 8 (Order 8 as it is called). Secondly, by arranging the numbers in the sequence as shown, each of the sum of the two individual diagonal lines supernaturally add up to the Magic Constant of 260. This means to say that those numbers in the two diagonal lines stay put. Over to you and all those interested. Shouldn’t be too difficult from here. Just juggle the numbers here and there, and you will have the solution. Cheers. geo
Posted on: 2007/6/4 18:36
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